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Why Aptitude Simple Equations is Required?

In this Aptitude section you can learn and practice Aptitude Questions with Answers based on "Simple Equations" to improve your skills in order to face written test by IT companies, interview and various entrance tests like Bank Exams, Railway Exams,ICET, GATE, CAT, GRE, MAT, etc.

Where can I get Aptitude Simple Equations Questions and Answers with Explanation?

AllIndiaExams provides you lots of fully solved Aptitude Simple Equations questions and answers with explanation. Fully solved examples with detailed answer description. All students, freshers can download Aptitude quiz questions with answers as PDF files and eBooks.

Where can I get objective type, multiple choice Aptitude Simple Equations Interview Questions and Answers?

Here you can find both objective type and Multiple Choice Aptitude Simple Equations questions and answers for interview and entrance examination. True or false type questions are also provided here. Practice these bits well to get success in interviews or entrance tests

How to solve these Aptitude Simple Equations problems?

You no need to worry, we have given lots of solved Aptitude Simple Equations questions with detailed explanation and also we have provided lots of short cut methods to quickly solve the questions within short time. So you can easily solve all kind of questions.

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Simple Equations - Aptitude Questions and Answers

This is aptitude questions and answers section on Simple Equations with the explanation for various interview, competitive examinations, and entrance tests. Learn and practice Simple Equations quiz in maths through the below provided questions and answers.

Simple Equations Questions - Simple Equations Quiz Details

Online Test Name Simple Equations
Exam Type Multiple Choice Questions
Category Aptitude Quiz
Number of Questions 30
1. Solve the equation for x : 6x - 27 + 3x = 4 + 9 - x
  • A. 4
  • B. 5
  • C. 6
  • D. -4
  • E. None of these
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Answer & Explanation

Answer: Option A

Explanation:

9 x + x = 13 + 27
10 x = 40 => x = 4

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2. Solve the equation for x : 19(x + y) + 17 = 19(-x + y) - 21
  • A. -1
  • B. -2
  • C. -3
  • D. -4
  • E. None of these
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Answer & Explanation

Answer: Option A

Explanation:

19x + 19y + 17 = -19x + 19y - 21
38x = -38 => x = -1

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3. The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
  • A. Rs.70
  • B. Rs.75
  • C. Rs.50
  • D. Rs.60
  • E. None of these
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Answer & Explanation

Answer: Option E

Explanation:

2C + 3T = 1300 --- (1)
3C + 3T = 1200 --- (2)
Subtracting 2nd from 1st, we get
-C + T = 100 => T - C = 100

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4. The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?
  • A. 2/3
  • B. 3/5
  • C. 4/7
  • D. 5/9
  • E. None of these
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Answer & Explanation

Answer: Option D

Explanation:

Let the numerator and denominator of the fraction be 'n' and 'd' respectively.
d = 2n - 1
(n + 1)/(d + 1) = 3/5
5n + 5 = 3d + 3
5n + 5 = 3(2n - 1) + 3 => n = 5
d = 2n - 1 => d = 9
Hence the fraction is : 5/9.

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5. The cost of 10 kg of apples is equal to the cost of 24 kg of rice. The cost of 6 kg of flour equals the cost of 2 kg of rice. The cost of each kg of flour is Rs.20.50. Find the total cost of 4 kg of apples, 3 kg of rice and 5 kg of flour?
  • A. Rs.849.40
  • B. Rs.877.40
  • C. Rs.901.60
  • D. Rs.815.20
  • E. None of these
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Answer & Explanation

Answer: Option B

Explanation:

Let the costs of each kg of apples and each kg of rice be Rs.a and Rs.r respectively.
10a = 24r and 6 * 20.50 = 2r
a = 12/5 r and r = 61.5
a = 147.6
Required total cost = 4 * 147.6 + 3 * 61.5 + 5 * 20.5
= 590.4 + 184.5 + 102.5 = Rs.877.40

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