This is aptitude questions and answers section on "Problems on Trains" with explanation for various interview, competitive examinations and entrance tests. Candidates can practice the Problems on Trains Quiz, Problems on Trains MCQ, Problems on Trains Aptitude Questions, Problems on Trains Multiple Choice Questions and Answers from the below section.
__Problems on Trains Questions - Problems on Trains Quiz Details__

__Problems on Trains Formulae__

1. km/hr to m/s conversion

a km/hr = (a x5/18) m/s

2. m/s to km/hr conversion

a m/s = (a x18/5) km/hr

Online Test Name |
Problems on Trains |

Exam Type |
Multiple Choice Questions |

Category |
Aptitude Quiz |

Number of Questions |
77 |

a km/hr = (a x5/18) m/s

2. m/s to km/hr conversion

a m/s = (a x18/5) km/hr

1. The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
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Answer: Option C

Explanation:

Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.

2. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
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Answer: Option D

Explanation:

Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time) = (50/3 * 9) m = 150 m.

3. A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
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Answer: Option B

Explanation:

Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==> x = 50 km/hr.

4. The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
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Answer: Option C

Explanation:

Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.

5. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
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Answer: Option B

Explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y = 3/2.