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Why Aptitude Mensuration is Required?

In this Aptitude section you can learn and practice Aptitude Questions with Answers based on "Mensuration" to improve your skills in order to face written test by IT companies, interview and various entrance tests like Bank Exams, Railway Exams,ICET, GATE, CAT, GRE, MAT, etc.

Where can I get Aptitude Mensuration Questions and Answers with Explanation?

AllIndiaExams provides you lots of fully solved Aptitude Mensuration questions and answers with explanation. Fully solved examples with detailed answer description. All students, freshers can download Aptitude quiz questions with answers as PDF files and eBooks.

Where can I get objective type, multiple choice Aptitude Mensuration Interview Questions and Answers?

Here you can find both objective type and Multiple Choice Aptitude Mensuration questions and answers for interview and entrance examination. True or false type questions are also provided here. Practice these bits well to get success in interviews or entrance tests

How to solve these Aptitude Mensuration problems?

You no need to worry, we have given lots of solved Aptitude Mensuration questions with detailed explanation and also we have provided lots of short cut methods to quickly solve the questions within short time. So you can easily solve all kind of questions.

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Mensuration - Aptitude Questions and Answers

This is aptitude questions and answers section on Mensuration with explanation for various interview, competitive examinations and entrance tests. Mensuration is an important topic for all those people who are preparing for competitive exams.

Mensuration Questions - Mensuration Quiz Details

Online Test Name Mensuration
Exam Type Multiple Choice Questions
Category Aptitude Quiz
Number of Questions 30

Mensuration Formulae

1. Rectangle
Area = lb
Perimeter = 2(l+b)

2. Square
Area = a2
Perimeter = 4a

3. Parallelogram
Area = bh
Perimeter = 2(a+b)

4. Triangle
Area =bh/2

5. Right angle Triangle
Area =1/2(bh)
Perimeter = b+h+d

6. Isosceles Right Angle Triangle
Area = 1/2. a2
Perimeter = 2a+d

7. Trapezium
Area = 1/2h(a+b)
Perimeter = Sum of all sides

8. Rhombus
Area = d1d2/2
Perimeter = 4l

9. Quadrilateral
Area =1/2 Diagonal (Sum of offsets)

10. Kite
Area = d1d2/2
Perimeter = 2 Sum on non-adjacent sides
1. What is the are of an equilateral triangle of side 16 cm?
  • A. 48√3 cm2
  • B. 128√3 cm2
  • C. 9.6√3 cm2
  • D. 64√3 cm2
  • E. None of these
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Answer & Explanation

Answer: Option D

Explanation:

Area of an equilateral triangle = √3/4 S2 

If S = 16, Area of triangle = √3/4 * 16 * 16 = 64√3 cm2;

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2. If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
  • A. 120 cm2
  • B. 130 cm2
  • C. 312 cm2
  • D. 315 cm2
  • E. None of thesae
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Answer & Explanation

Answer: Option A

Explanation:

The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.

Area of the triangle = 1/2 * 24 * 10 = 120 cm2

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3. The perimeter of a triangle is 28 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?
  • A. 25 cm2
  • B. 42 cm2
  • C. 49 cm2
  • D. 70 cm2
  • E. None of these
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Answer & Explanation

Answer: Option E

Explanation:

Area of a triangle = r * s

Where r is the inradius and s is the semi perimeter of the triangle.
Area of triangle = 2.5 * 28/2 = 35 cm2

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4. Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.
  • A. 225 cm2
  • B. 275 cm2
  • C. 285 cm2
  • D. 315 cm2
  • E. None of these
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Answer & Explanation

Answer: Option C

Explanation:

Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (20 + 18) * (15) = 285 cm2

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5. Find the area of a parallelogram with base 24 cm and height 16 cm.
  • A. 262 cm2
  • B. 384 cm2
  • C. 192 cm2
  • D. 131 cm2
  • E. None of these
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Answer & Explanation

Answer: Option B

Explanation:

Area of a parallelogram = base * height = 24 * 16 = 384 cm2

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