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## Analytical Puzzles Questions - Analytical Puzzles Quiz Details

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### Analytical Puzzles Questions

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Online Test Name |
Analytical Puzzles |

Exam Type |
Multiple Choice Questions |

Category |
Puzzles Quiz |

Number Of Questions |
175 Questions |

Candidates who want to take Analytical Puzzles Quiz for free of cost can stick to this article. We are helping postulates with the complete details regarding the Analytical Puzzles Online test which you need to follow while taking the test. To crack the online test, candidates have to practice the pre-mock tests compulsorily. That's why applicants can learn the Analytical Puzzles Multiple Choice Questions and answers from this article.

1. P, Q, R, S and T are five speakers who have to speak on a particular day, not necessarily in the same order. R is neither the first nor the last speaker. There are three speakers after S and three speakers ahead of T. If P speaks after Q, then who is the last speaker to speak?
### Answer & Explanation

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Answer: Option C

Explanation:

There are three speakers after S. So, S is the 2^{nd} speaker.

There are three speakers before T. So, T is the 4^{th} speaker.

R is neither the 1^{st} nor the 5^{th}. So, R is the 3^{rd} speaker.

P speaks after Q, So P is the 5^{th} and Q is the 1^{st} speaker. So, P is the last speaker.

2. Five persons - A, B, C, D and E are being compared in weight and height. The second heaviest person. D is the shortest. A is the 2^{nd} tallest and shorter than E, The heaviest person is the third tallest person. There is only one person shorter than B, who is lighter than E and A respectively.
### Answer & Explanation

A is shorter than E. So, the third tallest person is C. Who is the heaviest person. B is lighter than E and A respectively. So, the final arrangement is as follows.

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Who is the heaviest person?

Answer: Option C

Explanation:

A is the second tallest person. There is only one person shorter than B. So, B is the fourth tallest person. D is the shortest and second heaviest.

Weight | Height | |

1 | ||

2 | D | A |

3 | ||

4 | B | |

5 | D | |

Weight | Height | |

1. | C | E |

2. | D | A |

3. | E | C |

4. | A | B |

5. | B | D |

C is heaviest person.

3. 15 people entered a theater before Sujit. 7 people entered the theater between Sujit and Suraj and 20 people entered the theater after Suraj.

### Answer & Explanation

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How many people are there in the theater?

Answer: Option E

Explanation:

If Sujit entered before Suraj then the number of people will be 15 + 1(Sujit) + 7 + 1(Suraj) + 20 = 44.

If Suraj entered before Sujit then number of people will be 7 + 1(Suraj) + 7 + 1(Sujit) + 12 = 28.

So, the number of people in the theater cannot be determined.

4. A, B, C, D, E and F are six cities which are collinear in the same order. The distance between any two adjacent cities is equal. A bus starts at A for city F. It takes 25 minutes for the bus to travel from one city to another and stops for 5 minutes at each place. If the bus reaches E at 8:55, then at what time did it reach station B?
### Answer & Explanation

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Answer: Option A

Explanation:

Between B and E there are two intermediary stations C and D. For traveling from B to C, from C to D and from D to E it takes 3 * 25 = 75 minutes. At each of C and B it halts of 5 minutes. Hence, the time taken to reach E after starting at B is 85 minutes. i.e. one hour 25 minutes. Hence, it started at 7:30 at B. =>it reached B at 7:25.

5. P, Q, R, S, T and U are six cities which are in a row in the same order. A bus, b1 travels from P to U and another bus b2 travel from U to P. The bus b1 reaches S at 10:40 and bus b2 reaches Q at 10:35 if the travel time between any two adjacent cities is 40 minutes and the stoppage time at each city is 15 minutes, then at what time do they start at their respective destinations?
### Answer & Explanation

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Answer: Option C

Explanation:

The bus b1, which started at P, reached S at 10:40, passing through the intermediary cities Q and R.

The time taken to travel from P to S

= 3 * 40 + 2 * 15 = 150minute

(journey)+(stoppage)
= 2 hrs 30 minutes.

Hence, b1 started at 10:40 - 2:30 = 8:10 at P.

b2 reached Q, starting at U, through the city T, S and R.

The time taken by it to reach S = 4 * 40 + 3 * 15 = 205 minutes
= 3 hr 25 minutes.

Hence, b2 started at, 10:35 - 3:25 = 7:10, at U.