This is aptitude questions and answers section on Numbers and Ages with explanation for various interview, competitive examinations and entrance tests.

1. The sum of three consecutive integers is 102. Find the lowest of the three?
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Answer: Option D

Explanation:

Three consecutive numbers can be taken as (P - 1), P, (P + 1).

So, (P - 1) + P + (P + 1) = 102

3P = 102 => P = 34.

The lowest of the three = (P - 1) = 34 - 1 = 33.

2. The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?
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Answer: Option B

Explanation:

Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.

P + Q = 10 ----- (1)

(10Q + P) - (10P + Q) = 54

9(Q - P) = 54

(Q - P) = 6 ----- (2)

Solve (1) and (2) P = 2 and Q = 8

The required number is = 28

3. The sum of three consecutive even numbers is 42. Find the middle number of the three?
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Answer: Option A

Explanation:

Three consecutive even numbers (2P - 2), 2P, (2P + 2).

(2P - 2) + 2P + (2P + 2) = 42

6P = 42 => P = 7.

The middle number is: 2P = 14.

4. The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction?
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Answer: Option C

Explanation:

The denominator be P, the numerator will be (P - 8).

The fraction will be (P - 8)/P.

Adding 3 to the numerator and subtracting 3 from the denominator, (P - 8 + 3)/(P - 3) = 3/4.

(P - 5)/(P - 3) = 3/4

P = 20 - 9 => P = 11.

The fraction is: 3/11.

5. The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?
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Answer: Option C

Explanation:

A + B = 60, A = 2B

2B + B = 60 => B = 20 then A = 40.

5 years, their ages will be 45 and 25.

Sum of their ages = 45 + 25 = 70.

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