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## Numbers and Ages Questions - Numbers and Ages Quiz Details

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### Numbers and Ages Aptitude Questions

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### Numbers and Ages Formulae

Numbers

1. (a + b)(a - b) = (a2 - b2)

2. (a + b)2 = (a2 + b2 + 2ab)

3. (a - b)2 = (a2 + b2 - 2ab)

4. (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca)

5. (a3 + b3) = (a + b)(a2 - ab + b2)

6. (a3 - b3) = (a - b)(a2 + ab + b2)

7. (a3 + b3 + c3 - 3abc) = (a + b + c)(a2 + b2 + c2 - ab - bc - ac)

8. When a + b + c = 0, then a3 + b3 + c3 = 3abc.

Ages

1. Age after n years = X + n

2. Age n years ago = X – n

3. n times the age = nX

4. Age of y = (Ratio of y/Sum of ratios)× sum of ages

5. Age of y = (q/p+q)× A

### Numbers and Ages MCQ Quiz Answers With Solutions

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Online Test Name |
Numbers and Ages |

Exam Type |
Multiple Choice Questions |

Category |
Aptitude Quiz |

Number of Questions |
53 |

Viewers, learn and practice Numbers and Ages Aptitude Multiple Choice Questions and attempt Numbers and Ages Quiz for free of cost only on our site. Contenders should have a good grip on the Numbers and Ages Aptitude topic, and it will make the individuals sharpen up with the competitive world. Also, people must have good enough idea on the particular topic then only individuals should face Numbers and Ages Aptitude MCQ Online Test. Intenders can concentrate much on the preparation for Numbers and Ages Aptitude Quiz.

1. (a + b)(a - b) = (a2 - b2)

2. (a + b)2 = (a2 + b2 + 2ab)

3. (a - b)2 = (a2 + b2 - 2ab)

4. (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca)

5. (a3 + b3) = (a + b)(a2 - ab + b2)

6. (a3 - b3) = (a - b)(a2 + ab + b2)

7. (a3 + b3 + c3 - 3abc) = (a + b + c)(a2 + b2 + c2 - ab - bc - ac)

8. When a + b + c = 0, then a3 + b3 + c3 = 3abc.

Ages

1. Age after n years = X + n

2. Age n years ago = X – n

3. n times the age = nX

4. Age of y = (Ratio of y/Sum of ratios)× sum of ages

5. Age of y = (q/p+q)× A

1. The sum of three consecutive integers is 102. Find the lowest of the three?
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Answer: Option D

Explanation:

Three consecutive numbers can be taken as (P - 1), P, (P + 1).

So, (P - 1) + P + (P + 1) = 102

3P = 102 => P = 34.

The lowest of the three = (P - 1) = 34 - 1 = 33.

2. The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?
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Answer: Option B

Explanation:

Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.

P + Q = 10 ----- (1)

(10Q + P) - (10P + Q) = 54

9(Q - P) = 54

(Q - P) = 6 ----- (2)

Solve (1) and (2) P = 2 and Q = 8

The required number is = 28

3. The sum of three consecutive even numbers is 42. Find the middle number of the three?
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Answer: Option A

Explanation:

Three consecutive even numbers (2P - 2), 2P, (2P + 2).

(2P - 2) + 2P + (2P + 2) = 42

6P = 42 => P = 7.

The middle number is: 2P = 14.

4. The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction?
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Answer: Option C

Explanation:

The denominator be P, the numerator will be (P - 8).

The fraction will be (P - 8)/P.

Adding 3 to the numerator and subtracting 3 from the denominator, (P - 8 + 3)/(P - 3) = 3/4.

(P - 5)/(P - 3) = 3/4

P = 20 - 9 => P = 11.

The fraction is: 3/11.

5. The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?
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Answer: Option C

Explanation:

A + B = 60, A = 2B

2B + B = 60 => B = 20 then A = 40.

5 years, their ages will be 45 and 25.

Sum of their ages = 45 + 25 = 70.